81^x-1=(1/3)^x^2

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Solution for 81^x-1=(1/3)^x^2 equation: 



81^x-1=(1/3)^x^2

We move all terms to the left:

81^x-1-((1/3)^x^2)=0



Domain of the equation: 3)^x^2)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

81^x-((+1/3)^x^2)-1=0

We multiply all the terms by the denominator


81^x*3)^x^2)-((-1*3)^x^2)+1=0

We add all the numbers together, and all the variables

81^x*3)^x^2)-((-3)^x^2)+1=0

Wy multiply elements

243x^2-3)^x^2)+1=0

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